Find the equation of the ellipse whose vetices are `(pm6, 0)` and foci are `(pm 4, 0)`.

Explanation

Equation of ellipse can be given as

`x^2/a^2+y^2/b^2 = 1`


Here, Foci of ellipse ` = (+-4,0)`

So, `X`-axis is major axis and `c = 4`

Vertices of ellipse `= (+-6,0)`

`:.a = 6=>a^2 = 36`

`:. b^2 = a^2-c^2 = 36-16 = 20`

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