Find points on the curve `(x^2)/9+(y^2)/(16)=1`at which the tangents are(i) parallel to x-axis (ii) parallel to y-axis.

Explanation

To find the points on the curve \(\frac{x^2}{9} + \frac{y^2}{16} = 1\) where the tangents are parallel to the x-axis and y-axis, we will follow these steps:

### Step 1: Find the derivative \( \frac{dy}{dx} \)

Given the curve:
\[ \frac{x^2}{9} + \frac{y^2}{16} = 1 \]
...