Show that the tangents to the curve `y=7x^3+11` at the points where `x = 2` and `x = -2` are parallel.

Explanation

To show that the tangents to the curve \( y = 7x^3 + 11 \) at the points where \( x = 2 \) and \( x = -2 \) are parallel, we need to find the slopes of the tangents at these points and compare them.

### Step 1: Find the derivative of the function
The first step is to find the derivative of the function \( y = 7x^3 + 11 \). The derivative \( f'(x) \) gives us the slope of the tangent line at any point \( x \).

\[ f'(x) = \frac{d}{dx}(7x^3 + 11) = 21x^2 \]
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