For all real values of x, the minimum value of `(1-x+x^2)/(1+x+x^2)`is(A) 0 (B) 1 (C) 3 (D) `1/3`

Explanation

To find the minimum value of the function \( f(x) = \frac{1 - x + x^2}{1 + x + x^2} \), we will follow these steps:

### Step 1: Find the first derivative of the function
We will use the quotient rule for differentiation. The quotient rule states that if we have a function \( \frac{u}{v} \), then its derivative is given by:

\[ f'(x) = \frac{u'v - uv'}{v^2} \]
...