Find the slope of the tangent to the curve `y=x^3-3x+2` at the point whose x-coordinate is 3.

Explanation

To find the slope of the tangent to the curve \( y = x^3 - 3x + 2 \) at the point where the x-coordinate is 3, we will follow these steps:

### Step 1: Differentiate the function
We need to find the derivative of the function \( y \) with respect to \( x \). This derivative, denoted as \( \frac{dy}{dx} \), will give us the slope of the tangent line at any point on the curve.

Given:
\[
y = x^3 - 3x + 2
...