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Find the equation of the tangent to t...

Find the equation of the tangent to the curve `y=sqrt(3x-2)` which is parallel to the line `4x-2y+5=0.`

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If we differentiate the equation of curve we get slope of tangent at `(x,y)`
`y'=3/(2sqrt(3x−2))`
but tangent is parallel to line `4x-2y+5=0` there fore slope is `2`
that is `3/(2sqrt(3x−2))=2` ...
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NCERT ENGLISH-APPLICATION OF DERIVATIVES-EXERCISE 6.3
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