Find the maximum value and the minimum value and the minimum value of `3x^4-8x^3+12 x^2-48 x+25` on the interval `[0,3]dot`

Explanation

Let `f(x)`=`3x^4-8x^3-48 x-25`


Differentiate both sides with respect to x


`f'(x)`=`12x^3-24x^2-48`


For extreme point, `f(x)`=`0`


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