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Find the scalar components and magnitud...

Find the scalar components and magnitude of the vector joining the points `P(x_1,y_1,z_1)`and `Q(x_2,y_2,z_2)`

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To find the scalar components and magnitude of the vector joining the points \( P(x_1, y_1, z_1) \) and \( Q(x_2, y_2, z_2) \), we can follow these steps: ### Step 1: Write the Position Vectors The position vector of point \( P \) is given by: \[ \vec{P} = x_1 \hat{i} + y_1 \hat{j} + z_1 \hat{k} \] The position vector of point \( Q \) is given by: ...
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NCERT ENGLISH-VECTOR ALGEBRA-MISCELLANEOUS EXERCISE
  1. If theta is the angle between any two vectors veca and vec b, then...

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  2. The two adjacent sides of a parallelogram are 2 hat i-4 hat j+5 hat k ...

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  3. Show that the direction cosines of a vector equally inclined to the a...

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  4. Write down a unit vector in XY-plane, making an angle of 30° with the...

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  5. A girl walks 4 km towards west, and then she walks 3 km in a direction...

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  6. Find the scalar components and magnitude of the vector joining the po...

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  7. Find the value of x for which x( hat i+ hat j+ hat k)is a unit vector...

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  8. Let vec a= hat i+4 hat j+2 hat k , vec b=3 hat i-2 hat j+7 hat k and...

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  9. The scalar product of the vector hat i+ hat j+ hat kwith a unit vect...

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  10. If theta is the angle between two vectors veca and vecb, then veca...

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  11. Let veca and vecb be two unit vectors and is the angle between th...

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  12. If -> a , -> b , -> care mutually perpendicular vectors of equal ma...

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  13. Prove that (veca+ vecb)*( veca+ vecb)=|veca|^2+| vecb|^2, if and only ...

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  14. The value of hat i *( hat jxx hat k)+ hat j*( hat ixx hat k)+ hat k*...

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  15. यदि veca= vecb + vecc, तब क्या यह सत्य है कि | |veca| = |vecb| +|vecc|...

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  16. Find the position vector of a point R which divides the line joinin...

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  17. If veca= hat i+ hat j+ hat k, vecb=2 hat i- hat j+3 hat k and vecc...

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  18. Find a vector of magnitude 5 units, and parallel to the resultant of ...

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  19. Show that the points A(1,-2,-8) , B(5,0,-2) and C(11,3,7) are colline...

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