Find the angle between the two planes `3x - 6y + 2z = 7`and `2x + 2y-2z =5`.

Explanation

To find the angle between the two planes given by the equations \(3x - 6y + 2z = 7\) and \(2x + 2y - 2z = 5\), we can follow these steps:

### Step 1: Identify the normal vectors of the planes
The normal vector of a plane given by the equation \(ax + by + cz = d\) is \(\vec{n} = (a, b, c)\).

For the first plane \(3x - 6y + 2z = 7\):
- The coefficients are \(a = 3\), \(b = -6\), and \(c = 2\).
- Thus, the normal vector \(\vec{n_1} = (3, -6, 2)\).
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