Find the distance of the plane `2x - 3y + 4z - 6 = 0 `from the origin.

Explanation

To find the distance of the plane given by the equation \(2x - 3y + 4z - 6 = 0\) from the origin, we can use the formula for the distance \(D\) from a point \((x_1, y_1, z_1)\) to a plane given by the equation \(Ax + By + Cz + D = 0\):

\[ D = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \]

### Step-by-step solution:

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