Home
Class 6
MATHS
Find the least number which when divide...

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Text Solution

AI Generated Solution

To find the least number which, when divided by 6, 15, and 18, leaves a remainder of 5 in each case, we can follow these steps: ### Step 1: Understand the problem We need to find a number \( x \) such that: - \( x \mod 6 = 5 \) - \( x \mod 15 = 5 \) - \( x \mod 18 = 5 \) ...
Promotional Banner

Topper's Solved these Questions

  • PLAYING WITH NUMBERS

    NCERT ENGLISH|Exercise EXERCISE 3.1|4 Videos

  • PLAYING WITH NUMBERS

    NCERT ENGLISH|Exercise EXERCISE 3.5|12 Videos

  • MENSURATION

    NCERT ENGLISH|Exercise EXERCISE 10.2|1 Videos

  • RATIO AND PROPORTION

    NCERT ENGLISH|Exercise EXERCISE 12.1|16 Videos

Similar Questions

Explore conceptually related problems

Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case.

Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

Find the largest number which divides 245 and 1029 leaving remainder 5 in each case.

What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in each case?

Find the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case.

The greatest four digit number which when divided by 18 and 12 leaves a remainder of 4 in each case is (a) 9976 (b) 9940 (c) 9904 (d) 9868

Using Euclid's Algorithm, find the largest number which divides 870 and 258 leaving reminder 3 in each case .

Find the largest number , which divides 246 and 1030 leaving remainder 6 in each case.