If the speed of light is `3.0xx10^(8) m s^(-1)`, calculate the distance covered by light in `2.00 ns`.

Explanation

To solve the problem of calculating the distance covered by light in 2.00 ns, we will follow these steps:

### Step 1: Convert nanoseconds to seconds
We know that:
1 nanosecond (ns) = \(10^{-9}\) seconds.

Thus, to convert 2.00 ns to seconds:
\[ 2.00 \, \text{ns} = 2.00 \times 10^{-9} \, \text{s} \]

### Step 2: Use the formula for distance
The formula to calculate distance (d) when speed (v) and time (t) are known is:
\[ d = v \times t \]
Where:
- \(v\) is the speed of light, which is \(3.0 \times 10^{8} \, \text{m/s}\)
- \(t\) is the time in seconds, which we calculated as \(2.00 \times 10^{-9} \, \text{s}\)

### Step 3: Substitute the values into the formula
Now, we can substitute the values into the formula:
\[ d = (3.0 \times 10^{8} \, \text{m/s}) \times (2.00 \times 10^{-9} \, \text{s}) \]

### Step 4: Perform the multiplication
Calculating the multiplication:
\[ d = 3.0 \times 2.00 \times 10^{8} \times 10^{-9} \]
\[ d = 6.0 \times 10^{8 - 9} \]
\[ d = 6.0 \times 10^{-1} \, \text{m} \]
\[ d = 0.6 \, \text{m} \]

### Final Answer
The distance covered by light in 2.00 ns is \(0.6 \, \text{meters}\).

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