A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicualr to AC upto B, a distaance of 100m and looks at O and C again. Since O is very distant, the direction of BO is practically the same as AO, but he finds the line of sight of C shifted from the original line of sight by an angle `theta = 40^@ ( theta \ "is known as parallax").` Estimate the distance fo the tower C from his original position A.

Explanation

To estimate the distance of the tower C from the man's original position A, we can use the concept of parallax and trigonometry. Here’s a step-by-step solution:

### Step 1: Understand the Geometry of the Situation
- The man stands at point A, looking at the tower C and a distant object O.
- He walks 100 meters perpendicular to the line AC to point B.
- The angle of parallax (the shift in the line of sight to the tower C) is given as θ = 40°.

### Step 2: Set Up the Triangle
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