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Two resistors of resistances R(1)=100 pm...

Two resistors of resistances `R_(1)=100 pm 3` ohm and `R_(2)=200 pm 4` ohm are connected (a) in series, (b) in parallel. Find the equivalent resistance of the (a) series combination, (b) parallel combination. Use for (a) the relation `R=R_(1)+R_(2)` and for (b) `1/(R')=1/R_(1)+1/R_(2)` and `(Delta R')/R'^(2)=(Delta R_(1))/R_(1)^(2)+(Delta R_(2))/R_(2)^(2)`

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To solve the problem, we need to find the equivalent resistance of two resistors connected in series and in parallel, along with their uncertainties. ### Step-by-Step Solution: #### Part (a): Series Combination 1. **Identify the resistances and their uncertainties:** - \( R_1 = 100 \pm 3 \, \Omega \) ...
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NCERT ENGLISH-UNITS AND MEASUREMENT-EXERCISE
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