A substance weight 5.74 g occupies a volume of `1.2cm^3.` Caluclate its density with due regard to significant digits.

Explanation

There are 3 significant figures in the measured mass whereas there are only 2 significant figures in the measured volume. Hence the density should be expressed to only 2 significant figures.
Density `=5.74/1.2 g cm^(-3)`
`=4.8 g cm^(-3)`