A square lead slab of side 50 cm and thickness 10 cm is subjected to a shearing force (on its narrow face) of `9xx10^4N`. The lower edge is riveted to the floor. How much will the upper edge be displaced? (Shear modulus of lead`=5.6xx10^9Nm^-2`)

Explanation

To solve the problem, we need to calculate the displacement of the upper edge of the lead slab due to the applied shearing force. We will use the formula relating shear stress, shear strain, and shear modulus.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Side of the square slab (s) = 50 cm = 0.5 m
- Thickness of the slab (t) = 10 cm = 0.1 m
- Shearing force (F) = \(9 \times 10^4 \, \text{N}\)
...