A piece of copper having a rectangular cross section of `15.2 xx 19.1 mm` is pulled in tension with 45,500N, force producing only elastic deformation. Calculate the resulting strain. Shear modulus of elasticity of copper is `42 xx 10^(9)Nm^(-2)`.

Explanation

To solve the problem step by step, we will follow these instructions:

### Step 1: Convert dimensions to meters
The dimensions of the rectangular cross-section are given in millimeters. We need to convert them to meters.

- Length (L) = 15.2 mm = \( 15.2 \times 10^{-3} \) m
- Breadth (B) = 19.1 mm = \( 19.1 \times 10^{-3} \) m

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