A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1m, is whirled in a vertical circle with an angular velocity of `2 rev.//s` at the bottom of the circle. The cross-sectional area of the wire is `0.065 cm^(2)` . Calculate the elongaton of the wire when the mass is at the lowest point of its path `Y_(steel) = 2 xx 10^(11) Nm^(-2)`.

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Convert Angular Velocity
Given the angular velocity in revolutions per second (rev/s), we need to convert it to radians per second (rad/s).

\[ \omega = 2 \text{ rev/s} \times 2\pi \text{ rad/rev} = 4\pi \text{ rad/s} \approx 12.57 \text{ rad/s} \]
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