A `600 pF` capacitor is charged by a `200 V` supply. It is then disconnected from the supply and is connected to another uncharged `600 pF` capacitor. What is the common potential in `V` and energy lost in `J` afrte reconnection?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the initial charge on the charged capacitor

The charge \( Q \) on the capacitor can be calculated using the formula:
\[ Q = C \times V \]
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