Write resonance structures of `CH_(3)COO^(-)` and show the movement of electrons by curved arrows.

Explanation

To solve the problem of drawing the resonance structures of the acetate ion (CH₃COO⁻) and showing the movement of electrons with curved arrows, we can follow these steps:

### Step 1: Draw the Lewis Structure of CH₃COO⁻
- Start by determining the total number of valence electrons.
- Carbon (C) has 4, Oxygen (O) has 6, and Hydrogen (H) has 1.
- For CH₃COO⁻, we have 2 Carbons, 2 Oxygens, and 3 Hydrogens, plus an extra electron due to the negative charge.
- Total = (2 × 4) + (2 × 6) + (3 × 1) + 1 = 8 + 12 + 3 + 1 = 24 valence electrons.

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