Why does the following reaction occur?
`XeO_(6)^(4-)(aq)+2F^(Θ)(aq)+6H^(o+)(aq) rarr XeO_(3)(g)+F_(2)(g)+3H_(2)O(l)`
What conclusion about the compound `Na_(4)XeO_(6)` (of which `XeO_(6)^(4-)` is a part) can be drawn from the reaction?

Explanation

To understand why the reaction occurs, let's break down the steps involved in the reaction between \( \text{XeO}_6^{4-} \), \( \text{F}^- \), and \( \text{H}^+ \) to form \( \text{XeO}_3 \), \( \text{F}_2 \), and water.

### Step 1: Write the Reaction
The reaction can be summarized as follows:
\[ \text{XeO}_6^{4-}(aq) + 2\text{F}^-(aq) + 6\text{H}^+(aq) \rightarrow \text{XeO}_3(g) + \text{F}_2(g) + 3\text{H}_2O(l) \]

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