At a depth of 1000 m in an ocean (a) what is the absolute pressure? (b) what is the gauge pressure? (c ) Find the force acting on the window of area `20 cm xx 20cm` of a submarine at this depth, the interior of which is maintained at sea-level atmospheric pressure. The density of sea water is `1.03 xx 10^(3) kg m^(-3)`, `g=10ms^(-2)`. Atmospheric pressure = `1.01 xx 10^(5) Pa`.

Explanation

To solve the problem step by step, we will address each part of the question sequentially.

### Given Data:
- Depth (h) = 1000 m
- Density of seawater (ρ) = \(1.03 \times 10^3 \, \text{kg/m}^3\)
- Acceleration due to gravity (g) = \(10 \, \text{m/s}^2\)
- Atmospheric pressure (Pₐ) = \(1.01 \times 10^5 \, \text{Pa}\)
- Area of the window (A) = \(20 \, \text{cm} \times 20 \, \text{cm} = 0.2 \, \text{m} \times 0.2 \, \text{m} = 0.04 \, \text{m}^2\)
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