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A hydraulic automobile lift is designed ...

A hydraulic automobile lift is designed to lift cars with a maximum mass of 300 kg. the area of cross-section of the piston carrying the load is `425cm^(3)`. What maximum pressure would smaller piston have to bear?

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To solve the problem, we need to calculate the maximum pressure that the smaller piston must bear when lifting a car with a maximum mass of 300 kg. Here are the steps to find the solution: ### Step 1: Calculate the Force Exerted by the Car The force exerted by the car can be calculated using the formula: \[ F = m \cdot g \] where: ...
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A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm^(2). What maximum pressure would the small piston have to bear?

A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000Kg . The area of cross section of the piston carrying the load is 425cm^(2) . What maximum pressures would the smaller piston have to bear?

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NCERT ENGLISH-MECHANICAL PROPERTIES OF FLUIDS-EXERCISE
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