The cylinderical tube of a spray pump has a cross-section of `8.0cm^(2)` one end of which has 40 fine holes each of diameter 1.0mm. If the liquid flow inside the tube is 1.5 m per minute, what is the speed of ejection of the liquid through the holes?

Explanation

To solve the problem, we will use the principle of conservation of mass, which is expressed through the equation of continuity. This principle states that the mass flow rate must remain constant from one cross-section of a tube to another.

### Step-by-Step Solution:

1. **Convert the given flow velocity to meters per second:**
The liquid flow inside the tube is given as 1.5 m per minute. We need to convert this to meters per second.
\[
V_1 = 1.5 \, \text{m/min} = \frac{1.5}{60} \, \text{m/s} = 0.025 \, \text{m/s}
...