What is the pressure inside a drop of mercury of radius 3.0mm at room temperature? Surface tension of mercury at that temperature `(20^(@)C)` is `4.65xx10^(-1)Nm^(-1)`. The atmospheric pressure is `1.01xx10^(5)Pa`. Also give the excess pressure inside the drop.

Explanation

To solve the problem, we need to find the pressure inside a drop of mercury and the excess pressure inside the drop using the given parameters.

### Step-by-Step Solution:

1. **Convert the radius to meters**:
- Given radius \( R = 3.0 \, \text{mm} \).
- Convert mm to meters:
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