Calculate the heat required to convert 3 kg of ice at `-12^(@)C` kept in a calorimeter to steam at `100^(@)C` at atmospheric pressure. Given,
specific heat capacity of ice = `2100 J kg^(-1) K^(-1)`
specific heat capicity of water = `4186 J kg^(-1)K^(-1)`
Latent heat of fusion of ice = ` 3.35 xx 10^(5) J kg^(-1)`
and latent heat of steam = ` 2.256 xx 10^(6) J kg^(-1)` .

Explanation

To calculate the heat required to convert 3 kg of ice at -12°C to steam at 100°C, we need to consider several steps in the heating and phase change processes. The total heat required can be calculated by summing the heat required for each step.

### Step 1: Heating the Ice from -12°C to 0°C
The heat required to raise the temperature of the ice to 0°C can be calculated using the formula:
\[ Q_1 = m \cdot c_{ice} \cdot \Delta T \]
Where:
- \( m = 3 \, \text{kg} \) (mass of ice)
- \( c_{ice} = 2100 \, \text{J/kg/K} \) (specific heat capacity of ice)
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