Two ideal gas thermometer `A` and `B` use oxygen and hydrogen respectively . The following observations are made:
Temperature, Pressure therometer A, Pressure therometer B
Triple point of water, `1.250xx10^(5)Pa`, `0.200xx10^(5)Pa`
Normal melting point of sulphur, ` 1.797xx10^(5)Pa`, `0.287xx10^(5)Pa`
(a) What is the absolute temperature of normal melting point of sulphur as read by thermometers `A` and `B` ?
(b) What do you think is the reason for the slightly different answers from `A` and `B` ? (The thermometers are not faulty). what further procedure is needed in the experiment to reduce the discrepancy between the two readings.

Explanation

To solve the problem, we will calculate the absolute temperature of the normal melting point of sulfur as read by thermometers A and B using the ideal gas law. We will also discuss the reasons for the discrepancy in readings and suggest a procedure to reduce this discrepancy.

### Step-by-step Solution:

**Given Data:**
- For Thermometer A:
- Pressure at the triple point of water, \( P_{TR} = 1.250 \times 10^5 \, \text{Pa} \)
- Pressure at the normal melting point of sulfur, \( P_{M} = 1.797 \times 10^5 \, \text{Pa} \)
...