A child running a temperature of `101^F` is given and antipyrin (i.e. a madicine that lowers fever) which cause an increase in the rate of evaporation of sweat from his body. If the fever is brought down to `98^@F` in 20 min., what is the averatge rate of extra evaporation caused, by the drug ? Assume the evaporation mechanism to the only way by which heat is lost. The mass of the child is 30 kg. The specific heat of human body is approximately the same as that of water and latent heat of evaporation of water at that temperature is about `580 cal. g^(-1).`

Explanation

To solve the problem step by step, we will follow the given information and apply the principles of thermodynamics.

### Step 1: Gather Given Information
- Mass of the child, \( m = 30 \, \text{kg} = 30 \times 10^3 \, \text{g} \)
- Initial temperature, \( T_i = 101^\circ F \)
- Final temperature, \( T_f = 98^\circ F \)
- Time taken, \( t = 20 \, \text{minutes} \)
- Latent heat of evaporation of water, \( L = 580 \, \text{cal/g} \)
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