What is the radius of the path of an electron (mass `9 xx 10^(-31)` kg and charge `1.6 xx 10^(-19)C)` moving at a speed of `3 xx 10^(7)m//s` in a magnetic field of `6 xx 10^(-4)T` perpendicular to it? What is its frequency? Calculate its energy in `keV.(1eV = 1.6 xx 10^(-19)J)`.

Explanation

To solve the problem step by step, we will calculate the radius of the path of the electron, its frequency, and its energy in keV.

### Step 1: Calculate the radius of the path of the electron

The formula for the radius \( r \) of the circular path of a charged particle moving in a magnetic field is given by:

\[
r = \frac{mv}{qB}
...