A circular coil of wire consisting of 100 turns, each of radius `8.0cm` carries a current of `0.40A`.
What is the magnitude of the magnetic field `vecB` at the center of the coil?

Explanation

To find the magnitude of the magnetic field \( \vec{B} \) at the center of a circular coil, we can use the formula:

\[ B = \frac{\mu_0 \cdot I \cdot N}{2R} \]

where:
- \( B \) is the magnetic field at the center of the coil,
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