A tightly wound 100 turn coil of radius `10cm` is carrying a current of `1A`. What is the magnitude of the magnetic field at the centre of the coil?

Explanation

To find the magnitude of the magnetic field at the center of a tightly wound coil, we can use the formula for the magnetic field at the center of a circular loop of wire carrying a current. The formula is:

\[ B = \frac{\mu_0 \cdot I \cdot N}{2 \cdot R} \]

where:
- \( B \) is the magnetic field,
- \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} \)),
- \( I \) is the current,
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