A `3*0cm` wire carrying a current of `10A` is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be `0*27T`. What is the magnetic force on the wire?

Explanation

To find the magnetic force on a wire carrying current placed in a magnetic field, we can use the formula:

\[ F = IBL \sin \theta \]

Where:
- \( F \) is the magnetic force,
- \( I \) is the current in the wire,
- \( B \) is the magnetic field strength,
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