A magnetic needle has magnetic moment of `6*7xx10^-2Am^2` and moment of inertial of `7*5xx10^-6kgm^2`. It perform `10` complete oscillations in `6*70s`. What is the magnitude of the magnetic field?

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant formulas.

### Step 1: Identify the given values
- Magnetic moment (m) = \(6.7 \times 10^{-2} \, \text{A m}^2\)
- Moment of inertia (I) = \(7.5 \times 10^{-6} \, \text{kg m}^2\)
- Total time for 10 oscillations = \(6.70 \, \text{s}\)

### Step 2: Calculate the time period (T) for one oscillation
...