What is the magnitude of the equatorial and axial fields due to a bar manget of length `5*0cm` at a distance of `50cm` from its mid-point? The magnetic moment of the bar magnet is `0*40Am^2`.

Explanation

To solve the problem of finding the magnitude of the equatorial and axial fields due to a bar magnet, we will follow these steps:

### Given Data:
- Length of the bar magnet, \( L = 5.0 \, \text{cm} = 5.0 \times 10^{-2} \, \text{m} \)
- Distance from the midpoint, \( d = 50.0 \, \text{cm} = 50.0 \times 10^{-2} \, \text{m} = 0.50 \, \text{m} \)
- Magnetic moment, \( M = 0.40 \, \text{A m}^2 \)

### Step 1: Convert Length to Half
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