If the solenoid in the above question is free to turn about the vertical direction, and a uniform horizontal magnetic field of `0*25T` is applied, what is the magnitude of the torque on the solenoid when its axis makes an angle of `30^@` with the direction of the applied field?

Explanation

To find the magnitude of the torque on the solenoid when its axis makes an angle of \(30^\circ\) with the direction of the applied magnetic field, we can follow these steps:

### Step 1: Identify the given values
- Magnetic moment of the solenoid, \(m = 0.6 \, \text{J/T}\)
- Magnetic field strength, \(B = 0.25 \, \text{T}\)
- Angle with the magnetic field, \(\theta = 30^\circ\)

### Step 2: Use the formula for torque
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