A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north south direction. Null points are found on the axis of the magnet at `14cm` from the centre of the magnet. The earth's magnetic field at the plane is `0*36G` and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null points (i.e. 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and apposite to the horizontal component of earth's magnetic field).

Explanation

To solve the problem, we need to find the total magnetic field on the normal bisector of the magnet at a distance of 14 cm from the center of the magnet. We know that at the null points, the magnetic field due to the magnet is equal and opposite to the horizontal component of the Earth's magnetic field.

### Step-by-Step Solution:

1. **Understanding the Null Point Condition**:
At the null point, the magnetic field due to the bar magnet (B_m) is equal in magnitude and opposite in direction to the horizontal component of the Earth's magnetic field (H). Therefore, we can write:
\[
B_m = H
...