We are given the following atomic masses:
`._(92)^(238)U=238.05079u ._(2)^(4)He=4.00260u`
`._(90)^(234)Th=234.04363u ._(1)^(1)H=1.00783u`
`._(91)^(237)Pa=237.05121u`
Here the symbol `Pa` is for the element protactinium `(Z=91)`

Explanation

To solve the problem regarding the energy released during alpha decay of Uranium-238 and the possibility of spontaneous proton emission, we will follow these steps:

### Step 1: Write the decay equations
For alpha decay of Uranium-238:
\[ _{92}^{238}\text{U} \rightarrow _{90}^{234}\text{Th} + _{2}^{4}\text{He} \]

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