Suppose, we think of fission of a `._26Fe^(56)` nucleus into two equal fragments `._13Al^(28)`. Is the fission energetically possible? Argue by working out Q of the process. Given `m(._26Fe^(56))=55.93494u, m(._13Al^(28))=27.98191 u.`

Explanation

To determine if the fission of a \( _{26}^{56}\text{Fe} \) nucleus into two \( _{13}^{28}\text{Al} \) fragments is energetically possible, we need to calculate the Q value of the reaction. The Q value indicates the energy released or absorbed during the reaction. A positive Q value means the reaction is energetically favorable, while a negative Q value means it is not.

### Step-by-step Solution:

1. **Identify the Reaction**:
The fission process can be represented as:
\[
_{26}^{56}\text{Fe} \rightarrow 2 \times _{13}^{28}\text{Al}
...