The fission properties of `._84Pu^(239)` are very similar to those of `._92U^(235)`. The average energy released per fission is `180MeV`. How much energy in MeV is released if all the atoms in 1kg of pure `._94Pu^(239)` undergo fission.

Explanation

To solve the problem of how much energy is released if all the atoms in 1 kg of pure \( _{94}^{239}Pu \) undergo fission, we can follow these steps:

### Step 1: Determine the number of atoms in 1 kg of \( _{94}^{239}Pu \)

First, we need to calculate the number of atoms in 1 kg of \( _{94}^{239}Pu \). The number of atoms can be calculated using Avogadro's number and the molar mass of \( _{94}^{239}Pu \).

1. The molar mass of \( _{94}^{239}Pu \) is approximately 239 g/mol.
2. We convert 1 kg to grams: \( 1 \text{ kg} = 1000 \text{ g} \).
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