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How long can an electric lamp of 100W be kept glowing by fusion of 2.0 kg of deuterium? The fusion reaction can be taken as `._1H^2+._1H^2to ._1H^3+n+3.17MeV`

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To solve the problem, we need to determine how long a 100W electric lamp can be kept glowing using the energy released from the fusion of 2.0 kg of deuterium. We will follow these steps: ### Step 1: Calculate the energy released from the fusion of deuterium The fusion reaction given is: \[ _1H^2 + _1H^2 \rightarrow _1H^3 + n + 3.17 \text{ MeV} \] The energy released per reaction is 3.17 MeV. We need to convert this energy into joules. ...
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The binding energy of deuteron ._1^2 H is 1.112 MeV per nucleon and an alpha- particle ._2^4 He has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction ._1^2H + ._1^2h rarr ._2^4 He + Q , the energy Q released is.

The binding energy of deuteron ._1^2 H is 1.112 MeV per nucleon and an alpha- particle ._2^4 He has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction ._1^2H + ._1^2h rarr ._2^4 He + Q , the energy Q released is.

In the fusion reaction _1^2H+_1^2Hrarr_2^3He+_0^1n , the masses of deuteron, helium and neutron expressed in amu are 2.015, 3.017 and 1.009 respectively. If 1 kg of deuterium undergoes complete fusion, find the amount of total energy released. 1 amu =931.5 MeV//c^2 .

In the fusion reaction ._1^2H+_1^2Hrarr_2^3He+_0^1n , the masses of deuteron, helium and neutron expressed in amu are 2.015, 3.017 and 1.009 respectively. If 1 kg of deuterium undergoes complete fusion, find the amount of total energy released. 1 amu =931.5 MeV//c^2 .

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Scientists are working hard to develop nuclear fusion reactor Nuclei of heavy hydrogen, _(1)^(2)H , known as deuteron and denoted by D , can be thought of as a candidate for fusion rector . The D-D reaction is _(1)^(2) H + _(1)^(2) H rarr _(2)^(1) He + n+ energy. In the core of fusion reactor, a gas of heavy hydrogen of _(1)^(2) H is fully ionized into deuteron nuclei and electrons. This collection of _1^2H nuclei and electrons is known as plasma . The nuclei move randomly in the reactor core and occasionally come close enough for nuclear fusion to take place. Usually , the temperature in the reactor core are too high and no material will can be used to confine the to plasma for a time t_(0) before the particles fly away from the core. If n is the density (number volume ) of deuterons , the product nt_(0) is called Lawson number. In one of the criteria , a reactor is termed successful if Lawson number is greater then 5 xx 10^(14) s//cm^(2) it may be helpfull to use the following boltzmann constant lambda = 8.6 xx 10^(-5)eV//k, (e^(2))/(4 pi s_(0)) = 1.44 xx 10^(-9) eVm Result of calculations for four different design of a fusion reactor using D-D reaction are given below. which of these is most promising based on Lawson criterion ?

Scientists are working hard to develop nuclear fusion reactor Nuclei of heavy hydrogen, _(1)^(2)H , known as deuteron and denoted by D , can be thought of as a candidate for fusion rector . The D-D reaction is _(1)^(2) H + _(1)^(2) H rarr _(2)^(1) He + n+ energy. In the core of fusion reactor, a gas of heavy hydrogen of _(1)^(2) H is fully ionized into deuteron nuclei and electrons. This collection of _1^2H nuclei and electrons is known as plasma . The nuclei move randomly in the reactor core and occasionally come close enough for nuclear fusion to take place. Usually , the temperature in the reactor core are too high and no material will can be used to confine the to plasma for a time t_(0) before the particles fly away from the core. If n is the density (number volume ) of deuterons , the product nt_(0) is called Lawson number. In one of the criteria , a reactor is termed successful if Lawson number is greater then 5 xx 10^(14) s//cm^(2) it may be helpfull to use the following boltzmann constant lambda = 8.6 xx 10^(-5)eV//k, (e^(2))/(4 pi s_(0)) = 1.44 xx 10^(-9) eVm In the core of nucleus fusion reactor , the gas become plasma because of

Scientists are working hard to develop nuclear fusion reactor Nuclei of heavy hydrogen, _(1)^(2)H , known as deuteron and denoted by D , can be thought of as a candidate for fusion rector . The D-D reaction is _(1)^(2) H + _(1)^(2) H rarr _(2)^(1) He + n+ energy. In the core of fusion reactor, a gas of heavy hydrogen of _(1)^(2) H is fully ionized into deuteron nuclei and electrons. This collection of _1^2H nuclei and electrons is known as plasma . The nuclei move randomly in the reactor core and occasionally come close enough for nuclear fusion to take place. Usually , the temperature in the reactor core are too high and no material will can be used to confine the to plasma for a time t_(0) before the particles fly away from the core. If n is the density (number volume ) of deuterons , the product nt_(0) is called Lawson number. In one of the criteria , a reactor is termed successful if Lawson number is greater then 5 xx 10^(14) s//cm^(2) it may be helpfull to use the following boltzmann constant lambda = 8.6 xx 10^(-5)eV//k, (e^(2))/(4 pi s_(0)) = 1.44 xx 10^(-9) eVm In the core of nucleus fusion reactor , the gas become plasma because of

In a nuclear fusion reaction, the loss in mass is 0.3%. How much energy is released in the fusion of 1 kg mass ?

NCERT ENGLISH-NUCLEI-Exercise
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