Consider the fission `._(92)U^(238)` by fast neutrons. In one fission event, no neutrons are emitted and the final stable and products, after the beta decay of the primary fragments are `._(58)Ce^(140)` and `._(44)Ru^(99)`. Calculate Q for this fission process, The relevant atomic and particle masses are:
`m(._(92)U^(238))=238.05079u, m(._(58)Ce^(140))=139.90543 u, m(._(34)Ru^(99))=98.90594 u`

Explanation

To calculate the energy released (Q) during the fission of Uranium-238 by fast neutrons, we can follow these steps:

### Step 1: Write the Fission Reaction
The fission reaction can be represented as:
\[ _{92}^{238}U + n \rightarrow _{58}^{140}Ce + _{44}^{99}Ru \]
where \( n \) is the neutron that initiates the fission.
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