(Converse of Theorem 3) The line joining the centre of a circle to the
mid-point of a chord is perpendicular to the chord.
Text Solution
Verified by Experts
In `/_\AOX` and `/_\BOX`
`OA=OB` (radius)
`OX=OX` (Common)
`AX=BX` (given)
By SSS congruency, `/_\AOX` and `/_\BOX` are congruent.
`/_AXO=/_BXO` (CPCT) '
In line `AB`,
...
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