Statement 1 : The differential equation of all circles in a
plane must be of order 3.
Statement 2 : There is only one circle passing through three
non-collinear points.
Text Solution
Verified by Experts
In `/_\OPM` and `/_\OQM`
`OM=OM` (common)
`/_OMP=/_OMQ` (Perpendicular angles)
`PM=QM`
By SAS congruency, `/_\OPM` and `/_\OQM` are congruent.
`OP=OQ`
Similarly, we can prove that,
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