The perpendicular distance from origin to the line ax+by+c=0 is

Normal at (2, 2) to curve x^2 + 2xy – 3y^2 = 0 is L. Then perpendicular distance from origin to line L is

The perpendicular drawn from origin to the line y=mx+c meets the line at point (-1,-2) , (c,m)=?

(i ) If the length of perpendicular from origin to the line ax+by+a+b=0 is p , then show that : p^(2)-1=(2ab)/(a^(2)+b^(2)) (ii) If the length of perpendicular from point (1,1) to the line ax-by+c=0 is unity then show that : (1)/(a)-(1)/(b)+(1)/(C )=(c )/(2ab)

Find the perpendicular distance from the origin of the perpendicular from the point (1,2) upon the straight line x-sqrt(3)y+4=0

Find the perpendicular distance from the origin of the perpendicular from the point (1,2) upon the straight line x-3y+4=0.

The perpendicular distance of the origin from the plane which makes intercepts 12,3 and 4 on X, Y, and Z-axes respectively, is

If the length of the perpendicular from the point (1,1) to the line ax-by+c=0 be unity,show that (1)/(c)+(1)/(a)-(1)/(b)=(c)/(2ab)

Perpendicular distance from the origin to the line joining the points (a cos theta,a sin theta)(a cos phi,a sin phi) is

Find the equation of the line on which the length of the perpendicular segment from the origin to the line is 4 and the inclination of the perpendicular segment with the positive direction of x- axis is 30^(0) .