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A current of 0.2ampere is passes through...

A current of 0.2ampere is passes through a solution of `CuSO_4` for 10 minutes calculate the man of Cu deposited on the cathode.

Text Solution

Verified by Experts

`W=Q l t`
`W=E/96500 times I t`
`=(31.75 times 0.2 times 10 times 60)/96500`
`=0.03948 g`
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