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The conductivity of 0.001M acetic acid i...

The conductivity of 0.001M acetic acid is `4 times 10^-8 S//cm`. Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 `S cm^2//mol`.

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Verified by Experts

`A_m=(K times 1000)/m`
`=(4 times 10^-5 times 1000)/0.001`
`alpha=A_m/A_m^0=40/390=0.102`
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