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A force vec(F)=(3.00N)hat(i)+(7.00N) hat...

A force `vec(F)=(3.00N)hat(i)+(7.00N) hat(j) + (7.00N)hat(k)` act on a 2.00 kg mobile object that moves from an initial position of `vec(r_(i))=(3.00m)hat(i)-(2.00m)hat(j)+(5.00m)hat(k)` to a final position of `vec(r_(f))+(5.00m)hat(i)+(4.00m)hat(j)+(7.00m)hat(k)` in 4.00 s. Find the work done on the object by the force in the 4.00 s interval.

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AI Generated Solution

To find the work done on the object by the force in the given time interval, we can follow these steps: ### Step 1: Identify the Force Vector The force vector is given as: \[ \vec{F} = (3.00 \, \text{N}) \hat{i} + (7.00 \, \text{N}) \hat{j} + (7.00 \, \text{N}) \hat{k} \] ...
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