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During a storm, a crate of crepe is slid...

During a storm, a crate of crepe is sliding across a slick, oily parking lot through a displacement `vec(d)=(-3.0m)hat(i)` while a steady wind pushes against the crate with a force `vec(F)=(2.0N)hat(i)+(-6.0N)hat(j)`. The situation and coordinate axes are shown in Fig. 8-6.
If the crate has a kinetic energy of 10 J at the beginning of displacement `vec(d)`, what is its kinetic energy energy at the end of `vec(d)` ?

Text Solution

AI Generated Solution

To solve the problem, we will use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. The formula can be expressed as: \[ W = K_f - K_i \] Where: - \( W \) is the work done, - \( K_f \) is the final kinetic energy, - \( K_i \) is the initial kinetic energy. ...
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