Home
Class 12
PHYSICS
As a 2.5 kg body moves in the positive d...

As a 2.5 kg body moves in the positive direction along an `x` axis, a single force acts on it. The force is given by `F_(x)= -6x N`, with `x` in meters. The velocity at `x=3.5m` is 8.5 m/s. (a) Find the velocity of the body at `x=4.5` m. (b) Find the positive value of `x` at which the body has a velocity of 5.5 m/s.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Given Data: - Mass of the body, \( m = 2.5 \, \text{kg} \) - Force acting on the body, \( F_x = -6x \, \text{N} \) - Velocity at \( x = 3.5 \, \text{m} \), \( v = 8.5 \, \text{m/s} \) ### Part (a): Find the velocity of the body at \( x = 4.5 \, \text{m} \) 1. **Use Newton's Second Law**: \[ F = ma \implies -6x = m \frac{dv}{dt} \] Since \( a = \frac{dv}{dt} \) and we can express \( \frac{dv}{dt} \) in terms of \( \frac{dv}{dx} \): \[ -6x = m v \frac{dv}{dx} \] 2. **Rearranging the equation**: \[ v \, dv = -\frac{6}{2.5} x \, dx \] \[ v \, dv = -2.4 x \, dx \] 3. **Integrate both sides**: \[ \int v \, dv = \int -2.4 x \, dx \] \[ \frac{v^2}{2} = -1.2 x^2 + C \] 4. **Find the constant \( C \)** using the initial condition \( v = 8.5 \, \text{m/s} \) at \( x = 3.5 \, \text{m} \): \[ \frac{(8.5)^2}{2} = -1.2 (3.5)^2 + C \] \[ 36.125 = -1.2 \cdot 12.25 + C \] \[ 36.125 = -14.7 + C \implies C = 50.825 \] 5. **Substituting \( C \) back into the equation**: \[ \frac{v^2}{2} = -1.2 x^2 + 50.825 \] \[ v^2 = -2.4 x^2 + 101.65 \] 6. **Find \( v \) at \( x = 4.5 \, \text{m} \)**: \[ v^2 = -2.4 (4.5)^2 + 101.65 \] \[ v^2 = -2.4 \cdot 20.25 + 101.65 \] \[ v^2 = -48.6 + 101.65 = 53.05 \] \[ v = \sqrt{53.05} \approx 7.28 \, \text{m/s} \] ### Part (b): Find the positive value of \( x \) at which the body has a velocity of \( 5.5 \, \text{m/s} \) 1. **Set \( v = 5.5 \, \text{m/s} \)** in the equation: \[ (5.5)^2 = -2.4 x^2 + 101.65 \] \[ 30.25 = -2.4 x^2 + 101.65 \] \[ -2.4 x^2 = 30.25 - 101.65 \] \[ -2.4 x^2 = -71.4 \implies x^2 = \frac{71.4}{2.4} \] \[ x^2 = 29.75 \implies x = \sqrt{29.75} \approx 5.45 \, \text{m} \] ### Final Answers: - (a) The velocity of the body at \( x = 4.5 \, \text{m} \) is approximately \( 7.28 \, \text{m/s} \). - (b) The positive value of \( x \) at which the body has a velocity of \( 5.5 \, \text{m/s} \) is approximately \( 5.45 \, \text{m} \).
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER, AND ENERGY

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Single Correct Choice Type)|59 Videos
  • WORK, POWER, AND ENERGY

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (More than one choice correct type)|10 Videos
  • WORK, POWER, AND ENERGY

    RESNICK AND HALLIDAY|Exercise CHECKPOINT|6 Videos
  • WAVES-I

    RESNICK AND HALLIDAY|Exercise Practice Questions (Integer Type)|4 Videos

Similar Questions

Explore conceptually related problems

A body of mass 10 kg is upon by a force given by equation F=(3t^(2)-30) newtons. The initial velocity of the body is 10 m/s. The velocity of the body after 5 sec. is

A body moves with velocity v = lnx m/s where x is its position. The net force acting on body is zero at .

A block of mass 2 kg is having velocity 4sqrt(5) ms^(-1) in the positive x - direction at the origin. The only force acting on it is F = (3x^2 - 12 x)N . Its velocity when it is at x = 2 m is

The acceleration of a particle is given by the relation as a = -kv^(5//2) , where is a constant. The particle starts at x=0 with a velocity of 16 m/s, and when x = 6, the velocity is observed to be 4 m/s. Find the velocity of particle when x=5m and the time at which the velocity ofthe particle is 9 m/s.

A body of 5kg is moving with a velocity of 20m/s. If a force of 100N is applied on it for 10 s in the same direction as its velocity, what will now be the velocity of the body?

A particle is moving along x-axis. The position of the particle at any instant is given by x= a+bt^(2) where ,a= 6 m and b= 3.5 ms^(-2) 't' is measured in second .Find (i) the velocity of the particle at 1s and (ii) the average velocity between 3s and 6s

An object is moving along +ve x-axis with a uniform acceleration of 4ms^(-2) . At time t=0 , x=5m and v=3ms^(-1) . (a) What will be the velocity and position of the object at time t=2s? What will be the velocity and position of the object when it has a velocity of 5ms^(-1) ?

A body of mass 1kg is moving along a straight line with a velocity of 1m//s . The external force acting in the body is

The acceleration - time graph for a particle moving along x - axis is shown in figure, If the initial velocity of particle is -5m//s , the velocity at t = 8 s is

RESNICK AND HALLIDAY-WORK, POWER, AND ENERGY-PROBLEMS
  1. A spring of spring constant 5 xx 10^(2) Nm is streched initially by 5 ...

    Text Solution

    |

  2. A spring and block are in the arrangement of Fig. 8-12. When the bloc...

    Text Solution

    |

  3. As a 2.5 kg body moves in the positive direction along an x axis, a si...

    Text Solution

    |

  4. The block in Fig. 8-12a lies on a horizontal frictionless surface, and...

    Text Solution

    |

  5. The force on a particle is directed along an x axis and given by F= F(...

    Text Solution

    |

  6. A 1.0 kg block is initially at rest on a horizontal frictionless surfa...

    Text Solution

    |

  7. A particle of mass 0.020 kg moves along a curve with velocity 5.0 hat(...

    Text Solution

    |

  8. A can of cookies is made to move along an x axis from x=0.25 m to x= ...

    Text Solution

    |

  9. Only one force is acting on a 2.8 kg particle-like object whose positi...

    Text Solution

    |

  10. A force of 5.0 N acts on a 15 kg body initially at rest. Compute the w...

    Text Solution

    |

  11. A skier is pulled by towrope up frictionless ski slope that makes an a...

    Text Solution

    |

  12. Across a horizontal floor, a 102 kg block is pulled at a constant spee...

    Text Solution

    |

  13. The loaded cab of an elevator has a mass of 5.0 xx 10^(3) kg and moves...

    Text Solution

    |

  14. A machine carries a 4.0 kg package from an initial position of vec(d)(...

    Text Solution

    |

  15. A fully loaded, slow-moving freight elevator has a cab with a total ma...

    Text Solution

    |

  16. (a) At a certain instant, a particle-like object is acted on by a forc...

    Text Solution

    |

  17. A force vec(F)= (3.00 N) hat(i)+(7.00 N) hat(j)+(7.00 N) hat(k) acts o...

    Text Solution

    |

  18. A funny car accelerates from rest through a measured track distance in...

    Text Solution

    |

  19. Adam stretches a spring by some length. John stretches the same spring...

    Text Solution

    |

  20. A 1.50 kg snowball is fired from a cliff 11.5 m high. The snowball's ...

    Text Solution

    |