A force `vec(F)= (3.00 N) hat(i)+(7.00 N) hat(j)+(7.00 N) hat(k)` acts on a 2.00 kg mobile object that moves from an initial position of `vec(d)_(i) = (3.00 m) hat(i)- (2.00 m) hat(j)+ (5.00 m) hat(k)` to a final position of `vec(d)_(f)=-(5.00 m) hat(i) + (4.00 m) hat(j)+ (7.00 m) hat(k)` in 4.00 s. Find (a) the work done on the object by the force in the 4.00 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors `vec(d)_(i)` and `vec(d)_(f)`.

Answer

(a) `32.0 J; (b) 8.00 W; (c) 78.2^(@)`